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Posted: 9/1/2016 10:51:27 AM EDT
[#1]
y = 44-2x
x = 22 -y/2 Impossible to give actual values without another equation. |
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Posted: 9/1/2016 10:51:37 AM EDT
[#2]
No...one equation, two unknowns.
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Posted: 9/1/2016 10:52:21 AM EDT
[#3]
x = 81539
y = -163034 |
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Posted: 9/1/2016 10:54:20 AM EDT
[#4]
Sure. I can give you an infinite number of answers. Which one do you want.
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Posted: 9/1/2016 10:54:58 AM EDT
[#5]
Quote HistoryQuoted:
x = 81539y = -163034 No x = 21, and y = 2 
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Posted: 9/1/2016 10:55:49 AM EDT
[#6]
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Posted: 9/1/2016 10:58:05 AM EDT
[#7]
Quote HistoryQuoted:
y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. |
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Posted: 9/1/2016 10:58:17 AM EDT
[#8]
Q & D:
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Posted: 9/1/2016 10:58:33 AM EDT
[#9]
Quote HistoryQuoted:
No x = 21, and y = 2 Quote HistoryQuoted:
Quoted:
x = 81539y = -163034 No x = 21, and y = 2 I was thinking x=1 and y=42 But seriously, there's a shit ton of options there. |
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Posted: 9/1/2016 10:59:05 AM EDT
[#10]
y could be any number from 0 to 44 as long as you stay in the positive… If you include negative numbers it could be any number. |
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Posted: 9/1/2016 11:02:37 AM EDT
[#11]
Quote HistoryQuoted:
y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. um.....if you know what x and y are you can substitute them in the equation |
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Posted: 9/1/2016 11:03:09 AM EDT
[#12]
Quote HistoryQuoted: X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. Quote HistoryQuoted: Quoted: y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. You did a lot of unnecessary work to find one possible set of answers to a question with infinite sets of answers. |
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Posted: 9/1/2016 11:04:38 AM EDT
[#13]
Maybe my equation is wrong.
I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. |
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Posted: 9/1/2016 11:05:14 AM EDT
[#14]
Quote History
That's going to my wife, who is a math teacher. |
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Posted: 9/1/2016 11:05:32 AM EDT
[#15]
Quote HistoryQuoted: You did a lot of unnecessary work to find one possible set of answers to a question with infinite sets of answers. Quote HistoryQuoted: Quoted: Quoted: y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. You did a lot of unnecessary work to find one possible set of answers to a question with infinite sets of answers. Well, that, and it's also wrong.  2X=44-44+2X |
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Posted: 9/1/2016 11:07:45 AM EDT
[#16]
Quote HistoryQuoted: Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. Insufficient data to solve for x or y. |
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Posted: 9/1/2016 11:08:00 AM EDT
[#17]
Quote HistoryQuoted: Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem. |
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Posted: 9/1/2016 11:08:31 AM EDT
[#18]
Quote HistoryQuoted:
X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. Quote HistoryQuoted:
Quoted:
y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. Its AN answer, though arrived at erroneously. It is also not the only one. I gave the generalized answer. |
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Posted: 9/1/2016 11:09:06 AM EDT
[#19]
Quote HistoryQuoted:
um.....if you know what x and y are you can substitute them in the equation Quote HistoryQuoted:
Quoted:
y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. um.....if you know what x and y are you can substitute them in the equation Try it. Everything will cancel out, giving you no useful solution. |
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Posted: 9/1/2016 11:14:30 AM EDT
[#20]
They probably just want you to put it into slope-intercept form.
y = -2x + 44 -2 is the pitch in "rise over run" of the line on the graph and 44 is where the line will intercept the y-axis. |
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Posted: 9/1/2016 11:15:07 AM EDT
[#21]
Why not just set trip as 000.0 the next time you go to work. When you get there you will know that leg distance. You now have X. Put it in equation and you will find Y.
Or just set trip to 000.0 and drive back to gas station.
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Posted: 9/1/2016 11:18:55 AM EDT
[#22]
Quote HistoryQuoted:
The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem.
Quote HistoryQuoted:
Quoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem.
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer |
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Posted: 9/1/2016 11:19:19 AM EDT
[#23]
Quote HistoryQuoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. Drive to the gas station again and measure the distance. Subtract from 44. That is your distance to work. Ta da!!
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Posted: 9/1/2016 11:19:39 AM EDT
[#24]
Quote HistoryQuoted:
Why not just set trip as 000.0 the next time you go to work. When you get there you will know that leg distance. You now have X. Put it in equation and you will find Y. Or just set trip to 000.0 and drive back to gas station. But I would have to drive back to the gas station from my house |
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Posted: 9/1/2016 11:20:08 AM EDT
[#25]
x = x
y =y What do I win? |
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Posted: 9/1/2016 11:28:35 AM EDT
[#26]
Quote HistoryQuoted: Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. |
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Posted: 9/1/2016 11:34:14 AM EDT
[#27]
Quote HistoryQuoted:
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer Quote HistoryQuoted:
Quoted:
Quoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem.
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer The issue is that without fixing either the distance from GS to H or from H to W, the numbers in the equation can change on the line I graphed above. You have to fix one of the two or you have to drive home from somewhere else and then drive to work and back to give us another equation. That's how math works, and she doesn't give a shit. |
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Posted: 9/1/2016 11:40:00 AM EDT
[#28]
Quote HistoryQuoted:
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer Quote HistoryQuoted:
Quoted:
Quoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem.
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer Think of it this way... 2 of the trips could have been 10 miles (20 total) and the third trip could be 24 miles. That gets you to your total mileage. Or two of the trips could have been 5 miles (10 total) and the third trip would be 34 miles, also getting you to your 44 mile total. You can go on and on picking numbers that end up totaling 44 miles. It's not that your equation is unsolvable it's that there's more than a single correct answer. |
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Posted: 9/1/2016 11:40:33 AM EDT
[#29]
I can make that equation work with an infinity of numbers.
Make either the X or the Y a definite, and the other will be able to be solved as a definite as well. |
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Posted: 9/1/2016 11:42:17 AM EDT
[#30]
Why are you applying algebra to a fucking google maps problem?
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Posted: 9/1/2016 11:45:10 AM EDT
[#31]
Quote HistoryQuoted: I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer Quote HistoryQuoted: Quoted: Quoted: Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem. I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer |
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Posted: 9/1/2016 11:45:18 AM EDT
[#32]
Your equation for your problem is like me asking you "if I ate 3 apples from my bowl of apples, how many apples are left in the bowl."
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Posted: 9/1/2016 11:46:29 AM EDT
[#33]
You have two guys, guy a and guy b.
Either guy a or guy b is named mark, the other's is jim. What is guy a's name? Same deal here, two variables but only one equation that can be used to solve (except in math the possible solutions to this problem are infinite, the name problem is limited to two possible solutions). |
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Posted: 9/1/2016 11:46:56 AM EDT
[#34]
Quote HistoryQuoted:
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer Quote HistoryQuoted:
Quoted:
Quoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. The equation is correct, but more information is needed to solve for your instance. In order to define a single value to x, you need to know y, or vice-versa. This isn't a fancy math equation problem, this is a "how do I use the measure distance tool on Google Maps?" problem.
I don't know what else there is. I know I made three trips. I knkw two of those trips were the same and one trip was not. To me it is a pretty simple math problem and it is boggling my mind that I can't figure out how to do it without setting an odometer You can't find the solution because there is no relationship defined between your trip to the gas station and your trip to work. They are independent of one another; now if you said: the distance to work is three times the distance to the gas station (x=3y), you'd have a relationship between the two that makes the problem solvable. |
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Posted: 9/1/2016 11:50:29 AM EDT
[#35]
Quote HistoryQuoted:
Drive to the gas station again and measure the distance. Subtract from 44. That is your distance to work. Ta da!! Quote HistoryQuoted:
Quoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. Drive to the gas station again and measure the distance. Subtract from 44. That is your distance to work. Ta da!! No...he'd have to divide the answer by 2 to get his distance to work. |
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Posted: 9/1/2016 11:53:57 AM EDT
[#36]
Quote HistoryQuoted: But I would have to drive back to the gas station from my house Quote HistoryQuoted: Quoted: Why not just set trip as 000.0 the next time you go to work. When you get there you will know that leg distance. You now have X. Put it in equation and you will find Y. Or just set trip to 000.0 and drive back to gas station. But I would have to drive back to the gas station from my house Your address>gas station. Then (44-distance to gas station)/2 |
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Posted: 9/1/2016 12:00:46 PM EDT
[#37]
What if OP works at the gas station?
 x=y=14.6666
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Posted: 9/1/2016 12:03:39 PM EDT
[#38]
Depends on where the treadmill is.
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Posted: 9/1/2016 12:07:35 PM EDT
[#39]
Let's forget the math problem. The English fail in the title has got me confused.
"Can you solve for and y?" 
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Posted: 9/1/2016 12:12:38 PM EDT
[#40]
Quote HistoryQuoted:
Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. Y = odometer
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Posted: 9/1/2016 12:17:02 PM EDT
[#41]
You can't get a single answer for either x or y in your equation.
What you can do is get a graphing calculator to make a nifty line, since there is no single answer for either x or y in your equation. (don't forget to zoom out) |
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Posted: 9/1/2016 2:25:39 PM EDT
[#42]
Quote HistoryQuoted:
X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. Quote HistoryQuoted:
Quoted:
y = 44-2x x = 22 -y/2 Impossible to give actual values without another equation. X = 22 - (44-2X)/2 2X=44-44-2X 4X=0 X=0 Y=44 ...Is my math wrong? I haven't mathed in a long, long time. You still haven't mathed. 
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Posted: 9/1/2016 2:30:30 PM EDT
[#43]
Y is not a number.
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Posted: 9/1/2016 2:32:25 PM EDT
[#44]
X is 1
Y is 42 |
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Posted: 9/1/2016 2:44:55 PM EDT
[#45]
Quote HistoryQuoted:
Use google maps. Your address>gas station. Then (44-distance to gas station)/2 Quote HistoryQuoted:
Quoted:
Quoted:
Why not just set trip as 000.0 the next time you go to work. When you get there you will know that leg distance. You now have X. Put it in equation and you will find Y. Or just set trip to 000.0 and drive back to gas station. But I would have to drive back to the gas station from my house Your address>gas station. Then (44-distance to gas station)/2 This is your answer. |
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Posted: 9/1/2016 2:48:47 PM EDT
[#46]
Sometimes the simplest things baffle me. It looks this is one of those times for the OP. Don't sweat it OP, when you see it you'll smack your forehead, lol and say duh. |
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Posted: 9/1/2016 2:53:16 PM EDT
[#47]
Quote HistoryQuoted:
What if OP works at the gas station? x=y=14.6666
http://i281.photobucket.com/albums/kk228/SpudCrushr/Untitledasd_zps3dnxbg0y.png~original One of the most awesome GD MS Paint diagrams I've ever seen. Bar none. |
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Posted: 9/1/2016 2:53:26 PM EDT
[#48]
Quote HistoryQuoted:
X is 1 Y is 42 Or x is 22 and Y is 0. Or x is 15 and Y is 14. Or a few other possibilities. |
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Posted: 9/1/2016 2:55:10 PM EDT
[#49]
The rule of thumb in linear algebra is that you cannot solve for two variables when you only have one equation.
As others have noted, you can put in crapload of values for "x" and "y" and make this equation work, but there is no way to solve for a 'single answer' |
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Posted: 9/1/2016 2:56:29 PM EDT
[#50]
Quote HistoryQuoted: Maybe my equation is wrong. I drove from a gas station to my house (distance y). I then drive from my house to my job (distance x) and back to my house (distance x). I have 44 miles on my trip computer after doing that. I want to figure out how many miles each leg is. |
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