Equations you will never forget - Page 2

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Posted: 12/30/2012 6:57:47 AM EST

[#1]

E=mc2/sqrt(1-v2/c2)

Also, my avatar.

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Posted: 12/30/2012 7:01:10 AM EST

[#2]

Tragedy + Time = Comedy

Posted: 1/5/2013 7:58:41 AM EST

[#3]

Quoted:
two things from my math degree that I'll never forget:

This one looks familiar...

Another one I won't forget:

Posted: 1/10/2013 5:02:39 PM EST

[#4]

d = v*t (distance = veloctiy * time)
p = f/a (pressure = force / area)

Posted: 1/25/2013 2:55:30 PM EST

[#5]

Not an equation, but, easy to remember. values of colored bands on resistors.........."Bad Boys Rape Our Young Girls But Violet Gives Willingly"

Posted: 1/25/2013 6:11:42 PM EST

[#6]

Ah, too many to list. Off of the top of my head:

Newton's 2nd law:

Work/energy/potential:

Euler identity:

Fourier/diffusion law:

1D time-independent Schrodinger equation:

Canonical commutation:

Posted: 2/11/2013 12:01:20 PM EST

[#7]

(sum of integers from 1 to n) = n * (n + 1) / 2

Posted: 3/22/2013 6:27:58 AM EST

[#8]

Quoted:
v = ir
f=ma

f = ma

One of my personal favorites

Posted: 3/22/2013 6:30:06 AM EST

[#9]

(bh^2)/6 = Sx

(bh^3)/12 = Io

5wl^4/384EI = deflection

Posted: 3/22/2013 6:34:46 AM EST

[#10]

Quoted:
Avogadro's number = 6.0221415 x 10^23

We used to piss off Prof Richards by continuously calling this "Avocado's Number".

We never tired of that, nor did he.

Posted: 3/29/2013 6:05:23 PM EST

[#11]

Mississippi

As an engineer I'm way prouder that I can spell that.

Posted: 4/1/2013 6:58:34 PM EST

[#12]

Posted: 4/4/2013 1:03:33 PM EST

[#13]

Quoted:
http://i.imgur.com/nEALKD8.gif

http://i.imgur.com/4UTfKbV.gif

http://i.imgur.com/FFssZPG.gif

Hydraulics

Posted: 4/4/2013 3:45:58 PM EST

[#14]

Quoted:
Mississippi

As an engineer I'm way prouder that I can spell that.

But can you do it without singing it?

Don't lie, I have to sing it to spell it.

Posted: 4/4/2013 9:01:56 PM EST

[#15]

Quoted:

Quoted:

http://i.imgur.com/nEALKD8.gif

http://i.imgur.com/4UTfKbV.gif

http://i.imgur.com/FFssZPG.gif

Hydraulics

For some reason, out of everything, those equations have rang in my head through my entire PE power-cram for next week's exam...

I don't even use them to perform my current job! Why do *they* have such sticking power when I need my structural formwork more!

Posted: 4/5/2013 9:43:48 AM EST

[#16]

Quoted:

Quoted:
http://i.imgur.com/nEALKD8.gif

http://i.imgur.com/4UTfKbV.gif

http://i.imgur.com/FFssZPG.gif

Hydraulics

For some reason, out of everything, those equations have rang in my head through my entire PE power-cram for next week's exam. Haha!

I don't even use them to perform my current job! Why do *they* have such sticking power when I need my structural formwork more!

Good luck on the exam. Of course, it was much harder when I took it 35 years ago.

Posted: 4/6/2013 7:29:34 AM EST

[#17]

Quoted:

Quoted:

http://i.imgur.com/nEALKD8.gif

http://i.imgur.com/4UTfKbV.gif

http://i.imgur.com/FFssZPG.gif

Hydraulics

For some reason, out of everything, those equations have rang in my head through my entire PE power-cram for next week's exam. Haha!

I don't even use them to perform my current job! Why do *they* have such sticking power when I need my structural formwork more!

Good luck on the exam. Of course, it was much harder when I took it 35 years ago.

Thanks! And, yes and no.

I'll admit, I'm very thankful that it's not just a four complete write-out calculations, etc, partial-credit critiqued exam anymore like it was in the 80's. (the only previous exam style I've had 2nd hand knowledge, through my father)

MC with an average of 6 min/prob does present itself with some issues, though. It's either right or wrong, no partial credit for work performed, and those sneaky testmakers know exactly where we are likeliest to flub up our calcs, so they put those answers right in with the correct one. (Psychological skull-fk)

All-in-all, yes, I'd agree that it was probably much harder in the earlier forms of the exam, though I'd argue that it's not by leaps and bounds.

Now, back to studying. Only 6 more wake-ups.

Posted: 4/6/2013 7:46:23 AM EST

[#18]

Age/2+7

Posted: 4/6/2013 8:19:38 AM EST

[#19]

weight x G force / 75% rated tiedown device = number restraint chains required

Posted: 4/28/2013 8:01:22 AM EST

[#20]

Quoted:
W
A M

Beat into the head of every Loadmaster.

Weight X Arm = Moment/100,000 =C/B for a C17 (If I remember correctly...)

TIP
TW = C/B

TTFFTFTFT

Posted: 5/5/2013 8:23:32 AM EST

[#21]

Posted: 5/14/2013 4:16:39 AM EST

[#22]

Quoted:
K=1/2mv^2

A=(pi*D^2)/4

p1v1=p2v2

pv=nrt

A^2+B^2+C^2=D^2

P=(2st/d)FET (87 Internets to whoever knows that one)

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ok i am not a mathemagician, but here goes.

( sTpw™ + 3K9958V90M = pofnmsl)

I will purchase a team membrship for whomever figgers this one out, and do NOT have one, nor do i WANT ONE.
I am perfectly happy the way i am. I am gratefful for the service that the avilas provide to the community.

so even if you do figger it out ( highly unlikely) without the assistance of the internet, of the libeery o conngross.
dont buy me a membership>

Posted: 5/21/2013 3:30:34 PM EST

[#23]

Mnemonic:

Spuds if Pug Dish of Pig

Posted: 5/28/2013 12:04:31 PM EST

[#24]

Posted: 6/2/2013 8:51:18 PM EST

[#25]

Tan Apparent Dip = (Tan True Dip) X (Sin Angle of Proj)

Posted: 11/14/2013 6:35:54 PM EST

[#26]

F=d(mv)/dt

P=FV

Posted: 11/22/2013 4:32:37 PM EST

[#27]

Schrodingers solution to the hydrogen ion

Posted: 12/2/2013 10:43:03 AM EST

[#28]

marginal revenue equals marginal cost.

marginal rate of substitution = price ratio.

Posted: 1/5/2014 8:21:18 PM EST

[#29]

The Hardy Weinberg equation to determine genetic frequencies in a population p^2+2pq+q^2=1
p is the frequency of the dominant allele in a population
q is the frequency of the recessive allele in a population
pq is the frequency of heterozygotes in a population.
For a population to be in Hardy Weinberg equilibrium, there are several conditions that must be met, which
I won't go into here.

Posted: 1/9/2014 12:52:30 AM EST

[#30]

Pf=P_o10^SUR(t)

Posted: 1/15/2014 5:36:42 PM EST

[#31]

"Negative b plus or minus the square root of b squared minus 4ac, all over 2a." I'm taking college math courses again after a very long hiatus, and I was surprised how readily this one came to mind