[ARCHIVED THREAD] - Chance question (Page 1 of 2)
Posted: 10/27/2011 9:58:07 AM EDT
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. |
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Quoted: Quoted: Quoted: 50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. |
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Quoted: Quoted: Quoted: Quoted: Quoted: 50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? |
Thought those were extinct?
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. It's a bullshit question, I'd answer E) This question is retarded. If you had a 2 in 4 chance of answering correctly, then there's only 1 of 4 answers that would be correct (B - 50%) and thus your odds would be 1 in 4, no? Circular logic |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k And since only one of the answers is 50%, you really only had a 1 in 4 chance of getting it right. |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k And since only one of the answers is 50%, you really only had a 1 in 4 chance of getting it right. And if you only had a 1 in 4 chance of getting it right, the answer then changes, thus my post earlier stating it's circular logic and thus not "solvable". |
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Quoted: Quoted: Quoted: Quoted: Quoted: Quoted: Quoted: 50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k ROFL. Keep thinking...you'll get it eventually. If you have a 50% chance of getting the correct answer, then "50%" IS the correct answer, right? What are your odds, then, of picking the correct answer, since "50%" is only one of the four choices? |
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The question is stupid and not solvable based on the information given. This is correct. People are confusing the correct answer to the question with the actual probability of answering the question correctly. Since we don't know how many answers are considered correct, we can't determine the probability of guessing the correct answer, therefore we can't determine whether A,B,C or D is the correct answer.. |
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50 % since there is only one correct answer to the question, a,b,c or d, then a and d are not valid choices. leaving b and c, thus 1 of 2 or 50 % ie. b True, but the question is about picking a random answer.....from four choices. Posted Via AR15.Com Mobile Yes. If picked at random 1 in four chances would be 25% since two answers match that your odds have improved. The correct answer is 50%. ...but if the correct answer is "50%", then there's only a 1 in 4 chance you would choose it at random. See where this is going? Logic fail. Forget the numbers for a second. You have a one in four chance of selecting the correct answer of any question with four choices. Since two answers match you have a two in four chance of selecting 25% . That is why the answer is 50%. If the answer is 50%, then what does it matter what your chances are of selecting 25%? You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k And since only one of the answers is 50%, you really only had a 1 in 4 chance of getting it right. And if you only had a 1 in 4 chance of getting it right, the answer then changes, thus my post earlier stating it's circular logic and thus not "solvable". Exactly. |
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There are 4 marbles in a bag. Two red one white one blue. What are your odds of randomly picking a red marble? That's not what the question asks. In your question, 50% is the correct answer. In the OP's question, picking 50% makes 25% the right answer, while picking 25% makes 50% the correct answer. |
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You have a 25% chance of randomly picking the answer of any question with four choices. Since two of four are 25% you have a 50% chance of picking the correct answer. Got it? If all four choices were 25% you would have a 100% chance of picking the correct one answer. Do they really let some of you carry loaded guns? J/k And since only one of the answers is 50%, you really only had a 1 in 4 chance of getting it right. 50% is the answer, but the letter that corresponds to 50% is a red herring, you were never asked which letter was correct. I think... 
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If only 1 of 4 are correct, the only answer can be 25%. I say it's a tarp though. Posted Via AR15.Com Mobile 2 out of 4 choices = 50% 3 out of 4 choices is 75% and 75% is not offered as an answer...so 50% is the only answer. With only one 50%, you have a 25% chance of randomly choosing it. The sole purpose of that question is to mind-fuck and it works. |
The answer is either A, B, or D. It is unknown in which of the four 25%s the real answer lies. If it is in the first 25%, then the answer is A. If it is in either of the two middle 25%s, then the answer is B. If it is in the last 25%, then it follows that the answer is D. There is the possibility that one could choose C, but that contains only part of the 25%s and therefore is a wrong answer.
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I will try and lay it out logically.
You randomly select either a,b,c, or d If you select A you are declaring that the chances that you picked the correct number is 25%. However, you would be incorrect because in reality if that were the correct number you would have had a 50% chance of selecting it. (Due to D being the same answer). You would be Incorrect. If you select B you are declaring that you have a 50% chance of being correct. However, you would be incorrect because in reality if that were the correct number you would have had a 25% chance of picking it. You would be Incorrect. If you select C you are declaring that you have a 60% chance of being correct. However, you would be incorrect because in reality if that were the correct number you would have had a 25% chance of picking it. You would be Incorrect. If you select D you are declaring that you have a 25% chance of being correct. However, you would be incorrect because in reality if that were the correct number you would have had a 50% chance of picking it. (Due to A being the same answer). You would be Incorrect. Whether there is a correct answer other than A,B,C, or D is irrelevant because you have no option of selecting anything else. Therefore you will never be correct, so the chance of selecting the correct answer is 0% |