Posted: 1/18/2024 10:30:19 PM EDT
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Looking for a formula to figure the impact on an average with additional inputs. lets use individual input scores of 1 thru 5. lets say that there 275 inputs are ready and the current average is 4.7 Is there a formula to easily calculate what impact an additional input of a value would have on the overall average? Keeping in mind that each additional input value decreases the weighting of all current inputs. additionally how can you determine the number of top score (5) inputs it would require to raise the overall average from the current 4.7 to 4.8 and to 4.9? Rounding is done at 2 decimal points. thanks. |
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It would take 135 more 5s to raise it to 4.8 X=additional 5s needed 4.8(275+x)=5x+275*4.7 1320+4.8x=5x+1293 27=.2x 135=x Change it to 4.9 and x=550 |
Posterity! You will never know, how much it cost the present Generation, to preserve your Freedom! I hope you will make a good Use of it. If you do not, I shall repent in Heaven, that I ever took half the Pains to preserve it.---John Adams
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Originally Posted By intheburbs: It would take 135 more 5s to raise it to 4.8 X=additional 5s needed 4.8(275+x)=5x+275*4.7 1320+4.8x=5x+1293 27=.2x 135=x Change it to 4.9 and x=550 if I may ask 1 question: let say in the process of gathering the 135 additional 5 scores hoping to get to 4.8, a score of 1 was given. How far back would it alone set the process? How many more 5 score would it then take to recover from the low score and get to a 4.8 ? to my unmathematical mind, because there is much more room between 4.7 and 1 than there is between 4.7 and 5, a low score would have a more significant impact on the average than a high score would. Is this a truth? |
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Originally Posted By 03PSD: Amazing. Thank you. if I may ask 1 question: let say in the process of gathering the 135 additional 5 scores hoping to get to 4.8, a score of 1 was given. How far back would it alone set the process? How many more 5 score would it then take to recover from the low score and get to a 4.8 ? to my unmathematical mind, because there is much more room between 4.7 and 1 than there is between 4.7 and 5, a low score would have a more significant impact on the average than a high score would. Is this a truth? Yes, one bad score crushes it. A single "1" requires an additional 20 5s to offset it and raise to 4.8. The starting equation would change to... 4.8(276+x)=5x+1294 And solving for x gives 155 now to raise to 4.8. A single "1" would require 30 more 5s to raise to 4.9. |
Posterity! You will never know, how much it cost the present Generation, to preserve your Freedom! I hope you will make a good Use of it. If you do not, I shall repent in Heaven, that I ever took half the Pains to preserve it.---John Adams
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Originally Posted By intheburbs: Yes, one bad score crushes it. A single "1" requires an additional 20 5s to offset it and raise to 4.8. The starting equation would change to... 4.8(276+x)=5x+1294 And solving for x gives 155 now to raise to 4.8. A single "1" would require 30 more 5s to raise to 4.9. As the number of input values increases, the impact (good or bad) decreases, correct? If you had 550 input scores, double the original number, to begin with would it then require double the amount of 5 scores to move up to 4.8 and 4.9? 270 and 1100 respectively? There comes a point where it almost impossible in a practical sense to increase the average but still exists a comparatively easy way for the average to drop. |
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Originally Posted By FredMan: All I know is pulling my 0.929 GPA after 3 semesters to a 3.2 at graduation was a bitch kitty. |
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Scenario: You have 275 inputs with an average score of 4.7. Scores range from 1 to 5. How to calculate the new average after adding one more score: Use this formula: New Average = (Current Total + New Score) / (Current Count + 1) In this case: New Average = (275 * 4.7 + x) / 276 Replace x with the new score (1 to 5) to see how it affects the average. How many additional perfect scores (5s) are needed to raise the average? Use this formula: k = (Target Average * Current Count - Current Average * Current Count) / (5 - Target Average) Where: k = number of additional 5s needed Current Count = 275 Current Average = 4.7 Target Average = 4.8 or 4.9 To raise the average from 4.7 to 4.8: k = (4.8 * 275 - 4.7 * 275) / (5 - 4.8) k = (1320 - 1292.5) / 0.2 k = 27.5 / 0.2 k = 137.5 So you'd need at least 138 perfect 5s to hit a 4.8 average. To raise the average from 4.7 to 4.9: k = (4.9 * 275 - 4.7 * 275) / (5 - 4.9) k = (1347.5 - 1292.5) / 0.1 k = 55 / 0.1 k = 550 So you'd need 550 perfect 5s to hit a 4.9 average. Summary: You can use the average formula to see the effect of new scores. To raise the average, you need more and more high scores the closer you get to 5, because each new score slightly dilutes the weight of the previous ones. |
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ProTip: Never pick a fight with a tree planter. He swings a hoedad for 9 hours a day, carries 30-40 pounds of seedlings on his back, and has 12-14 friends just like him hiding out on the other side of the junk butt pile. They will fuck your shit up.
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Originally Posted By 03PSD: D is for degree. Unless you're in the top .1% of so called elite institutions, no one in the real worlds give a damn what your GPA was, thankfully! If anything the nerds who graduate with the highest honors are socially inept and cannot deal with the real world in many cases. I cared! |
ProTip: Never pick a fight with a tree planter. He swings a hoedad for 9 hours a day, carries 30-40 pounds of seedlings on his back, and has 12-14 friends just like him hiding out on the other side of the junk butt pile. They will fuck your shit up.