Posted: 9/30/2010 1:53:52 PM EDT
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My teacher sucks, anyone want to teach me how to do the problem?
Michael jordan was playing basketball. He was fouled and went to the free throw line. Before he shot he was averaging 78% of his free throws. He made one out of 2 and his percentage dropped to 76%. How many free throws had he attempted and made before he went to the free throw line? |
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Quoted: Public school. It's a miracle I know how to tie my shoes.Quoted: No, a math nerd would be needed to help you with your Laplace transform or solve some tensor equations. What you need is someone who graduated the 10th grade with a B in math. if it took you until 10th grade to learn how to do that...  |
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So
.78y = x and .76y + 1.52 = x+1 simplified down: .76y + .52 = x sub x: .76y + .52 = .78y .52 = .02y y = 26 sub y back into original equation.... .78(26) = x x = 20.28 Thanks a lot genius' but please explain to me how somebody makes 20.28 out of 26 freethrows... the answer has to be in whole numbers. The teacher left out one fact...here it is: 78% means he was making between 77.5% and 78.5% of his free throws I know this should have been included earlier but I posted what he initially gave us, this is new info that should make a difference. Here's my shot at it: X/Y <= .785 x/y >= .775 (x+1) = .76 (y+2) I have to admit I'm stuck here because I haven't learned how to do all this jazz. Any help would be greatly appreciated! |
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I think your math might have gone astray:
x/y = .78, so x = .78y, that's right. (x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y = .76(y+2) .78y = .76y + 1.52 .02y = 1.52 y = 76 So x = .78 * 76 = 59.28 But that's not a whole number! So lets round to the nearest whole number: x = 59. And guess what? 59/76 = 77.6% and 77.5% < 77.6% < 78.5% Edited to fix retarded typo. |
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Quoted:
I think your math might have gone astray: x/y = .78, so x = .78y, that's right. (x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y = .76(y+2) .78y = .76y + 1.52 .02y = 1.52 y = 76 So x = .78 * 76 = 59.28 But that's not a whole number! So lets round to the nearest whole number: x = 59. And guess what? 59/76 = 77.6% and 77.5% < 77.6% < 78.5% Edited to fix retarded typo. In the red... x+1 is replaced by .78y? or should it be .78y+1....? |
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I think your math might have gone astray: x/y = .78, so x = .78y, that's right. (x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y = .76(y+2) .78y = .76y + 1.52 .02y = 1.52 y = 76 So x = .78 * 76 = 59.28 But that's not a whole number! So lets round to the nearest whole number: x = 59. And guess what? 59/76 = 77.6% and 77.5% < 77.6% < 78.5% Edited to fix retarded typo. In the red... x+1 is replaced by .78y? or should it be .78y+1....? You're correct, he should have put (.78y)+1=.76y+1.52 .78y=.76y+.52 .02y=.52 y=26 Edit: y as 26 isn't working out for me though.. |
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Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/27 = 77.7% which is well within the given range. I think I just muddied things up, apologies. |
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Quoted:
Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/2728 = 77.7%75% which is well within the given range. I think I just muddied things up, apologies. |
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Quoted: I love these threads. Nothing funnier than mathematical insults.  My high school calc teacher would refer to any asshole as a third derivative. The intuition is this. Take a position function y. Then, y'=velocity y''=acceleration y'''=acceleration of the acceleration. So, y''' denotes "jerks." So, if you are a third derivative of a position function, you are a jerk. |
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Quoted: Quoted: Holy crap, really? You really need help with this? Made throws / total throws = made percentage X / Y = 0.78 (X + 1) /( Y + 2) = 0.76 You can do the rest. At this point, solve x/y=.78 for one variable, and plug it in to the other equation. This will give you the number of the other variable. Plug that number back into x/y=.78 for the other one. |
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I love these threads. Nothing funnier than mathematical insults. My high school calc teacher would refer to any asshole as a third derivative. The intuition is this. Take a position function y. Then, y'=velocity y''=acceleration y'''=acceleration of the acceleration. So, y''' denotes "jerks." So, if you are a third derivative of a position function, you are a jerk.
Yeah, but this problem is so easy. I thought it would have been over and done with after 5 posts. Yet............... |
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No, a math nerd would be needed to help you with your Laplace transform or solve some tensor equations. What you need is someone who graduated the 10th grade with a B in math. if it took you until 10th grade to learn how to do that... Public school. It's a miracle I know how to tie my shoes. If you didn't learn the Ian's Knot, then you're doing it incorrectly. |
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Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/2728 = 77.7%75% which is well within the given range. I think I just muddied things up, apologies. I'm fairly dense tonight, bear with me. 21/27 = 77.7% and 77.5% < 77.7% < 78.5%, additionally 22/29 = 75.9% which is roughly 76%, which fits with how the freethrow percentage dropped after making 1 of 2 more. Why do we want 75%? |
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Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/2728 = 77.7%75% which is well within the given range. I think I just muddied things up, apologies. I'm fairly dense tonight, bear with me. 21/27 = 77.7% and 77.5% < 77.7% < 78.5%, additionally 22/29 = 75.9% which is roughly 76%, which fits with how the freethrow percentage dropped after making 1 of 2 more. Why do we want 75%? Ohh my bad, I thought you were saying the original numbers were 20/26, which would then make the new proportion of successful shots/total 21/28. My bad. |
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Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/2728 = 77.7%75% which is well within the given range. I think I just muddied things up, apologies. I'm fairly dense tonight, bear with me. 21/27 = 77.7% and 77.5% < 77.7% < 78.5%, additionally 22/29 = 75.9% which is roughly 76%, which fits with how the freethrow percentage dropped after making 1 of 2 more. Why do we want 75%? Ohh my bad, I thought you were saying the original numbers were 20/26, which would then make the new proportion of successful shots/total 21/28. My bad. Gotcha. Yeah, I mean, solving the given equations and rounding does give me 20/26, but that doesn't jive with the given %'s. I just happened to notice that 21/27 does. Would you believe I code 3D graphics for a living? 
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Glad I saved my smart ass remarks about GD averaging 160 IQs. Let's take another look:
(x+1)/(y+2) = .76 (x+1) = .76(y+2) .78y + 1 = .76(y+2) .78y = .76y + .52 .02y = .52 y = 26 so then x = .78y = 20.28 Unfortunately rounding gives me 20 freethrows and 20/26 = 76.9%. FWIW, 21/2728 = 77.7%75% which is well within the given range. I think I just muddied things up, apologies. I'm fairly dense tonight, bear with me. 21/27 = 77.7% and 77.5% < 77.7% < 78.5%, additionally 22/29 = 75.9% which is roughly 76%, which fits with how the freethrow percentage dropped after making 1 of 2 more. Why do we want 75%? Ohh my bad, I thought you were saying the original numbers were 20/26, which would then make the new proportion of successful shots/total 21/28. My bad. Gotcha. Yeah, I mean, solving the given equations and rounding does give me 20/26, but that doesn't jive with the given %'s. I just happened to notice that 21/27 does. Would you believe I code 3D graphics for a living? well I sincerely appreciate the effort in assisting. Knowing this professor he probably mixed up some numbers and the given percentages will never work out to a whole number. I'll have to wait until Tuesday of next week for class to find out what the hell is going on, it will bug me until then. In the meantime if I happen to have an epiphany I will be sure to post it here. Thanks for all of the help!!! |
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well I sincerely appreciate the effort in assisting. Knowing this professor he probably mixed up some numbers and the given percentages will never work out to a whole number. I'll have to wait until Tuesday of next week for class to find out what the hell is going on, it will bug me until then. In the meantime if I happen to have an epiphany I will be sure to post it here. Thanks for all of the help!!! You're welcome! I look forward to hearing the resolution. |
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Quoted: Quoted: Quoted: Quoted: No, a math nerd would be needed to help you with your Laplace transform or solve some tensor equations. What you need is someone who graduated the 10th grade with a B in math. if it took you until 10th grade to learn how to do that... Public school. It's a miracle I know how to tie my shoes. If you didn't learn the Ian's Knot, then you're doing it incorrectly. I like to go around the tree and down the rabbit hole and shit. You know, in terms I can understand. |
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