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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? View Quote It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: |
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This thread occurs, and yet polls about IQs on here are consistently skewed a deviation or two to the right. Non sequitur.
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So according to physics, if my plane is flying 2000fps and my bullet is fired rearward at 2000fps, the bullet would just remain where it left the barrel, and begin falling straight down??? Yes. An Aggie said it! /thread |
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Quoted: Does that mean if you put a flash light on the front of an aircraft going at Mach 4, that the light coming out from the front of the flash light will be going at the speed of light+Mach 4? ...effectively FASTER than the speed of light? View Quote View All Quotes View All Quotes Quoted: Quoted: Since the bullets are stationary relative to the motion of the aircraft they will be going the same speed of the aircraft. When they are fired you add the increased velocity to the now fired projectile. Does that mean if you put a flash light on the front of an aircraft going at Mach 4, that the light coming out from the front of the flash light will be going at the speed of light+Mach 4? ...effectively FASTER than the speed of light? Light behaves much differently than objects which follow the Newtonian subset of physics. The speed of light remains the same despite the speed of any object it is traveling. |
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It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Mach 2 is rougly 2k fps, depending on some variables. |
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So according to physics, if my plane is flying 2000fps and my bullet is fired rearward at 2000fps, the bullet would just remain where it left the barrel, and begin falling straight down??? Yes. An Aggie said it! /thread Ah, but consider firing a the same gun from inside the plane facing rearward. Is would still appear to travel at 2000fps right? That's because the plane is traveling at 2000fps, while the bullet remains static. Correct? |
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Only if the cannon fires a laser beam instead of a projectile. View Quote View All Quotes View All Quotes Quoted:
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Thou shalt not add thy velocity to the speed of light. Same principle applies here. Also only if the cannon is actually a fricken shark with fricken laser beams. |
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Quoted: It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc View Quote View All Quotes View All Quotes Quoted: Quoted: This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Yes it is. The bullet fired would travel away from the plane at 3450 fps. Meaning ground speed would be 3450 + plane speed. If you're saying the bullet has 3450 fps and the plane matched that speed (if possible) the bullet wouldn't leave the barrel. That's false. |
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The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. View Quote |
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Now, if you had instead asked about a spaceship traveling at the speed of light turning on its headlights, that would have been an interesting question
Warp 2 that was easy Quoted:
The speed of sound is irrelevant. Let's perform a thought experiment. A plane is flying at 500 MPH = 733 FPS. It fires a projectile from its cannon at 2,000 FPS. The projectile is travelling at 2,733 FPS. Now a plane is flying at 1,000 MPH (speed of sound is ca. 761 MPH) = 1,466 FPS. It fires a projectile from its cannon at 2,000 FPS. The projectile is traveling at 1,466 = 2,000 FPS = 3,466 FPS. "Mach" is irrelevant. Now, if you had instead asked about a spaceship traveling at the speed of light turning on its headlights, that would have been an interesting question. View Quote View All Quotes View All Quotes Quoted:
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Dang, all these answers and only two of them serious! So all you physics experts that think I am stupid, can you dumb it down just a LITTLE bit to explain what will happen? The speed of sound is irrelevant. Let's perform a thought experiment. A plane is flying at 500 MPH = 733 FPS. It fires a projectile from its cannon at 2,000 FPS. The projectile is travelling at 2,733 FPS. Now a plane is flying at 1,000 MPH (speed of sound is ca. 761 MPH) = 1,466 FPS. It fires a projectile from its cannon at 2,000 FPS. The projectile is traveling at 1,466 = 2,000 FPS = 3,466 FPS. "Mach" is irrelevant. Now, if you had instead asked about a spaceship traveling at the speed of light turning on its headlights, that would have been an interesting question. |
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Mach 2 is rougly 2k fps, depending on some variables. View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Mach 2 is rougly 2k fps, depending on some variables. OOPS - I converted a M/S vs MPH in a calculator. My bad. |
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Quoted: Quoted: Quoted: So according to physics, if my plane is flying 2000fps and my bullet is fired rearward at 2000fps, the bullet would just remain where it left the barrel, and begin falling straight down??? Yes. An Aggie said it! /thread Your avatar is appropriate. |
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When you are running and you throw a ball forward do you run into the ball?
ETA: Planes can only run into their own ordinance if they accelerate enough after they fire it or the bullet has slowed enough to overtake it. |
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Only if the cannon fires a laser beam instead of a projectile. View Quote View All Quotes View All Quotes Quoted:
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Thou shalt not add thy velocity to the speed of light. Same principle applies here. It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. |
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OOPS - I converted a M/S vs MPH in a calculator. My bad. View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Mach 2 is rougly 2k fps, depending on some variables. OOPS - I converted a M/S vs MPH in a calculator. My bad. It happens. |
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Ah, but consider firing a the same gun from inside the plane facing rearward. Is would still appear to travel at 2000fps right? That's because the plane is traveling at 2000fps, while the bullet remains static. Correct? View Quote View All Quotes View All Quotes Quoted:
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So according to physics, if my plane is flying 2000fps and my bullet is fired rearward at 2000fps, the bullet would just remain where it left the barrel, and begin falling straight down??? Yes. An Aggie said it! /thread Ah, but consider firing a the same gun from inside the plane facing rearward. Is would still appear to travel at 2000fps right? That's because the plane is traveling at 2000fps, while the bullet remains static. Correct? Bullet travels @ 2K fps relative to the cannon. So when the 20mm HEI hits the back wall of the cockpit, the plane blows up, killing our intrepid experimenter. Thanks a bunch! |
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Quoted: When you are running and you throw a ball forward do you run into the ball? View Quote There are plenty of genius level IQs in this thread that would argue the ball wouldn't leave your hand. Or that you aren't imparting any extra velocity to the ball by running. They think that you can pitch a ball 70mph standing still but if you're in the back of a pickup traveling at 70mph and you throw the ball forward, it's only going to go 70 mph. Derp. |
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Quoted: It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. View Quote View All Quotes View All Quotes Quoted: Quoted: Quoted: Thou shalt not add thy velocity to the speed of light. Same principle applies here. It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. Well at least you understand velocity relative to the barrel but velocity relative to the ground seems to elude you. |
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There are plenty of genius level IQs in this thread that would argue the ball wouldn't leave your hand. Or that you aren't imparting any extra velocity to the ball by running. They think that you can pitch a ball 70mph standing still but if you're in the back of a pickup traveling at 70mph and you throw the ball forward, it's only going to go 70 mph. Derp. Actually, that's a very good analogy. And the ball will travel at 70 mph. Less by a bit due to the size of the baseball and wind resistance. View Quote View All Quotes View All Quotes Quoted:
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When you are running and you throw a ball forward do you run into the ball? They think that you can pitch a ball 70mph standing still but if you're in the back of a pickup traveling at 70mph and you throw the ball forward, it's only going to go 70 mph. Derp. Actually, that's a very good analogy. And the ball will travel at 70 mph. Less by a bit due to the size of the baseball and wind resistance. |
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Yes it is. The bullet fired would travel away from the plane at 3450 fps. Meaning ground speed would be 3450 + plane speed. If you're saying the bullet has 3450 fps and the plane matched that speed (if possible) the bullet wouldn't leave the barrel. That's false. View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Yes it is. The bullet fired would travel away from the plane at 3450 fps. Meaning ground speed would be 3450 + plane speed. If you're saying the bullet has 3450 fps and the plane matched that speed (if possible) the bullet wouldn't leave the barrel. That's false. OK - that's right. You do get the extra speed initially. But they loose velocity as soon as the exit the barrel. If you were traveling faster than the bullet can fly it will still exit the barrel (the pressure forces it out, speed isn't a factor). But the plane can travel fast enough to over take it shortly after. Per my link a an example of it happening. |
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It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. View Quote View All Quotes View All Quotes Quoted:
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Thou shalt not add thy velocity to the speed of light. Same principle applies here. It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. I think you fail to understand the concept of frame of reference. |
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Quoted: The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. View Quote can you picture how wrong that is? |
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Quoted: Quoted: Quoted: When you are running and you throw a ball forward do you run into the ball? They think that you can pitch a ball 70mph standing still but if you're in the back of a pickup traveling at 70mph and you throw the ball forward, it's only going to go 70 mph. Derp. Actually, that's a very good analogy. And the ball will travel at 70 mph. Less by a bit due to the size of the baseball and wind resistance. |
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are you suggesting that if my aircraft was flying at a velocity of 2799 fps and I fired my cannon at 2800 that the bullet would exit the barrel and move off at ONE fps? can you picture how wrong that is? View Quote View All Quotes View All Quotes Quoted:
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The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. can you picture how wrong that is? With Respect To the cannon. The motion of the cannon relative to the Ground Observer is significant in this mental exercise. Vectors, how's dey work, anyhow? EDIT: Thread has provided a much need laugh here. While confusing to some, thinking about relative motion is legit and I hope all the peeps in this thread make sense of it. |
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All of this would be interesting at speeds approaching C (3E8). Otherwise it is Newtonion and only interesting in the amount of ignorance it brings to the surface.
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The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. View Quote where are you standing? say for example you are in a aircraft traveling at 500MPH. Nolan Ryan is at the rear of the aircraft (inside the aircraft, for the dense people here...) you are at the front of the aircraft (inside the aircraft, for the dense people here...) Nolan winds up and throws a 90MPH fastball towards you. how fast is the baseball traveling? to the observers seated in the aircraft, the baseball is traveling at 90MPH. (in fact, inside the aircraft you could measure this with a standard issue radar gun.) one would say that these observers are in one reference plane, one which is moving along with the aircraft. to the observers on the ground, that same baseball is traveling at 590MPH. (500+90MPH) one would say that these observers are in another reference plane, one which not moving along with the aircraft. suppose you and Nolan Ryan exchange positions; he's at the front of the aircraft, you are at the rear. again, he throws a 90MPH fastball at you. to the observers seated in the aircraft, the baseball is traveling at 90MPH. to the observers on the ground, that same baseball is traveling at 410MPH. (500-90MPH) suppose you and Nolan Ryan exchange positions AGAIN; he's is once again at the rear of the aircraft, you are at the front. again, he throws a 90MPH fastball at you. this pitch is high, though. you duck out of the way, and the baseball sails through the open cabin door and then goes straight through the aircraft windshield. (let's ignore for the moment the fact that the glass slowed the baseball somewhat) at the moment the baseball comes out the front of the aircraft, how fast is it traveling? hint: you already know the answer from this post. now go re-read your question above. ar-jedi |
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Quoted: Yes it is. The bullet fired would travel away from the plane at 3450 fps. Meaning ground speed would be 3450 + plane speed. If you're saying the bullet has 3450 fps and the plane matched that speed (if possible) the bullet wouldn't leave the barrel. That's false. View Quote View All Quotes View All Quotes Quoted: Quoted: Quoted: This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. But even Mach 2 is only ~1000 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc Yes it is. The bullet fired would travel away from the plane at 3450 fps. Meaning ground speed would be 3450 + plane speed. If you're saying the bullet has 3450 fps and the plane matched that speed (if possible) the bullet wouldn't leave the barrel. That's false. |
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It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. View Quote View All Quotes View All Quotes Quoted:
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Thou shalt not add thy velocity to the speed of light. Same principle applies here. It would seem that if the conditions the OP postulates obtain then it would be a well understood phenomenon, especially by the worlds various air forces and fighter pilots. It's simply not how it works. A projectile that has a charge giving it a mv of x when fired from a barrel on the ground doesn't exit a barrel at x*2 when fired from a moving platform. What the hell are you talking about? |
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"... Examination of the F11F established there were three hits—in the windshield, the right engine intake, and the nose cone. The engine's inlet guide vanes were struck, and a battered 20mm projectile was found in the first compressor stage.. http://www.aerofiles.com/cleardot.gif How did this happen? The combination of conditions reponsible for the event was (1) the decay in projectile velocity and trajectory drop; (2) the approximate 0.5-G descent of the F11F, due in part to its nose pitching down from firing low-mounted guns; (3) alignment of the boresight line of 0° to the line of flight. With that 0.5-G dive, Attridge had flown below the trajectory of his bullets and, 11 seconds later, flew through them as their flight paths met.." So, Pappy Boyington didn't really shoot down 28 Japanese planes, as some were simply victims of flying through his misses? View Quote View All Quotes View All Quotes Quoted:
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Velocity of Plane (1100 fps) + Velocity of Bullet at muzzle (3000 fps)= 4100 fps (speed of bullet for one split second till aerodynamics take over). Immediately leaving the barrel the bullet will be going fast, but losing velocity as soon as it leaves the barrel. Since the plane has the power to keep it's speed the plane will catch the bullet eventually. So, yes a plane can shoot itself down if it comes into the path of it's own bullets. Ground observer will see bullet going 4100 fps and the plane will see it going 3000 fps. "... Examination of the F11F established there were three hits—in the windshield, the right engine intake, and the nose cone. The engine's inlet guide vanes were struck, and a battered 20mm projectile was found in the first compressor stage.. http://www.aerofiles.com/cleardot.gif How did this happen? The combination of conditions reponsible for the event was (1) the decay in projectile velocity and trajectory drop; (2) the approximate 0.5-G descent of the F11F, due in part to its nose pitching down from firing low-mounted guns; (3) alignment of the boresight line of 0° to the line of flight. With that 0.5-G dive, Attridge had flown below the trajectory of his bullets and, 11 seconds later, flew through them as their flight paths met.." So, Pappy Boyington didn't really shoot down 28 Japanese planes, as some were simply victims of flying through his misses? Semantics. |
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It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc your own video shows you to be wrong |
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Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. View Quote I' having a hard time seeing how could it be otherwise? If the pilot dropped the bullet out of the window of the aircraft at 750Mph, what is the velocity of the bullet relative to a ground observer? |
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I am in the front of a 747 with an open nose traveling at 570 MPH and I step out at a rate of 3 MPH, how fast am I traveling? How do I even overcome the blast of a 570 MPH wind bearing down on me? View Quote View All Quotes View All Quotes Quoted:
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You are in the back of a 747 that is travelling at 570 mph, and you start to walk at a rate of 3 mph to the front of the plane. How fast are you travelling? I am in the front of a 747 with an open nose traveling at 570 MPH and I step out at a rate of 3 MPH, how fast am I traveling? How do I even overcome the blast of a 570 MPH wind bearing down on me? You can not possibly be this stupid. I'll try to dumb it down for you even more. The plane is moving at the speed of X (for the sake of argument lets call X a thousands miles an hour, but it can be 500, 2000, 4, 10,000, or 10,000,000 it doesn't matter). The gun is in the plane. So the gun is also moving at X because it is in the plane. Are you with me so far? The bullet is in the gun. The gun as we have established is moving at X therefor the bullet, being in the gun, must also be moving at X. Understand? Now the bullet, which is already moving at X, is fired. It has a muzzle velocity of Y (let's call Y 2,000 feet per second, but again, it does not matter). So the bullet which is ALREADY moving at X is pushed forward from its STARTING SPEED of X at the rate of Y. So the bullet's speed relative to the plane,which is also moving at X, is only Y, or in this case 2,000 feet per second, but to the ground it is moving at X+Y, or 1,000 miles an hour PLUS 2,000 feet per second. Now,do an experiment. Get on your bike and peddle as fast as you can, faster than you can gently throw a tennis ball, now while you are moving, gently throw a tennis ball, come back and tell us what happened. What will happen is that from your perspective the tennis ball was gently thrown, moved away from you as normal, and bounced off the ground, from an observers perspective who was not moving the ball was moving like a pro tennis serve and smacked off the ground at high speed because itwas moving at the speed of the bike, PLUS the speed of the throw. Get it yet? Try another experiment. Get on the bus and while its moving at 40ish miles per hour get up, and walk toward the front of the bus? Could you move? Did you fly out the rear window? But the bus was moving at 40 miles per hour and you were moving at just 1.5, how could that be? Because before you got out of your seat, you were ALSO going 40 miles per hour, so when you got up you were moving at 1.5 miles per hour relative to the bus, which to you, since you are also going 40 miles per hour, is stationary, but to an observer standing watching, your speed was 41.5 miles per hour, or the speed of the bus PLUS the speed you were walking, so you were actually walking FASTER than the bus. Understand yet? |
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It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc You are missing the concept of vectors. A vector includes the magnitude (in this case the velocity) and direction. When an object is launched forward in the same direction of the vehicle then you add the velocities. When the object is launched backwards like in the video, you still add the velocities, but the object is moving in the negative direction (thus subtracting). If a car is moving at 10 m/s and a ball is thrown backwards at 10 m/s, then in the perspective of a person on the sidewalk the ball will only bounce up and down instead of rolling in any direction. 10 + (-10) = 0 |
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So according to physics, if my plane is flying 2000fps and my bullet is fired rearward at 2000fps, the bullet would just remain where it left the barrel, and begin falling straight down??? View Quote Only relative to an outside observer at 0 MPH. Think of it another way. Say a plane flies past you on the ground at 750mph and you shoot a bullet that can reach 700MPH at the plane as it moves away..... can your bullet hit the aircraft? Certainly not. Now say you are following 100yds behind at 750Mph and you fire your 700Mph bullet at it. Can you you now hit the plane? Certainly so. |
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc your own video shows you to be wrong The video shows what happens if you shot it backwards - not forwards. In that case IIRC the truck shot the ball at 60mph while it traveled at 60mph. The link explains what happens when you shoot a bullet forwards at high speeds and shows how it is possible to shoot yourself down. |
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You are missing the concept of vectors. A vector includes the magnitude (in this case the velocity) and direction. When an object is launched forward in the same direction of the vehicle then you add the velocities. When the object is launched backwards like in the video, you still add the velocities, but the object is moving in the negative direction (thus subtracting). If a car is moving at 10 m/s and a ball is thrown backwards at 10 m/s, then in the perspective of a person on the sidewalk the ball will only bounce up and down instead of rolling in any direction. 10 + (-10) = 0 View Quote View All Quotes View All Quotes Quoted:
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This question that has been tickling my brain. I'm sure it never happens, but what if a fighter fired its gun at speeds above Mach? Would the projectiles be Mach plus their normal speed??? Would the projectiles just fall out of the barrel and keep pace with the plane? Could a plane shoot itself down? I have read that the B-58 had its rear firing cannon removed because it could fly faster than the projectiles it fired could leave the barrel. What say the collective GD mind? It will go as fast as any normal bullet would. In the case of the 20mm Vulcan, wiki says 3,450 feet per second. It isn't 3450 + the speed of the plane. You initially get the speed of the plane and then the speed of the bullet , but the bullet starts to slow down the moment it leave the barrel - and especially if the plane speeds up, it can hit the plane. By comparison, Mach 2 is about 2200 feet per second. But yes, if the plane is going faster than the bullet, then the bullet will hit the plane. The bullet is only accelerating until it reaches the end of the barrel. Here is an account of a pilot who shot his own plane in a dive in the 50s. His bullets I think were slower than the modern Vulcan, though. http://www.check-six.com/Crash_Sites/Tiger138260.htm Here is a Mythbusters video showing what would happen if you shot a bullet out of a plane backwards and were going as fast as the bullet. The bullet would leave the barrel because of the pressure, but then this happens: http://www.youtube.com/watch?v=BLuI118nhzc You are missing the concept of vectors. A vector includes the magnitude (in this case the velocity) and direction. When an object is launched forward in the same direction of the vehicle then you add the velocities. When the object is launched backwards like in the video, you still add the velocities, but the object is moving in the negative direction (thus subtracting). If a car is moving at 10 m/s and a ball is thrown backwards at 10 m/s, then in the perspective of a person on the sidewalk the ball will only bounce up and down instead of rolling in any direction. 10 + (-10) = 0 Yes - they are two different things. He mentioned tail gunners flying faster than their bullets, which is why I included the second video. |
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The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. View Quote You're trolling, right? RIGHT? You cannot be that dumb. I hope. But ok, here ya go. X = vehicle velocity Y = gun muzzle velocity Z = total projectile velocity X+Y=Z Simple enough, Einstein? So, vehicle velocity = 2000fps.(X) gun muzzle velocity = 2800fps.(Y) total projectile velocity = 2000+2800=4800fps (Z) TADA! |
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You're trolling, right? RIGHT? You cannot be that dumb. I hope. View Quote View All Quotes View All Quotes Quoted:
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The projectile sitting in the chamber of the gun is motionless in relation to the chamber, barrel, etc. If the muzzle velocity of the projectile is 2,800 fps, the muzzle velocity is 2,800 fps regardless of the aircraft velocity. Show me an equation that demonstrates a .50 cal projectile, or any other, gains an additional 2,000 fps by being fired from an aircraft traveling at such speed. You're trolling, right? RIGHT? You cannot be that dumb. I hope. Physics is hard, yo. |
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps?
I don't think so. |
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps? I don't think so. View Quote Your avatar is VERY fitting. It is 4800fps, sherlock. |
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Your avatar is VERY fitting. It is 4800fps, sherlock. View Quote View All Quotes View All Quotes Quoted:
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps? I don't think so. Your avatar is VERY fitting. It is 4800fps, sherlock. No, it is not 4,800 fps. eta.. how the fuck would ground crews ever be able to regulate the guns if they had to take into account the varying speed of the aircraft? Even at 400 mph that would create problems. |
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps? I don't think so. Your avatar is VERY fitting. It is 4800fps, sherlock. No, it is not 4,800 fps. Actually, it is. But keep on being wrong. Your choice. To the plane, the bullet would be moving away at 2800fps. To the observer, the bullet would be coming towards at 4800fps. |
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No, it is not 4,800 fps. eta.. how the fuck would ground crews ever be able to regulate the guns if they had to take into account the varying speed of the aircraft? Even at 400 mph that would create problems. View Quote View All Quotes View All Quotes Quoted:
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps? I don't think so. Your avatar is VERY fitting. It is 4800fps, sherlock. No, it is not 4,800 fps. eta.. how the fuck would ground crews ever be able to regulate the guns if they had to take into account the varying speed of the aircraft? Even at 400 mph that would create problems. JESUS FUCKING CHRIST. REALLY? REALLLLLLLLLY DOOD? I'm embarrassed for you. |
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JESUS FUCKING CHRIST. REALLY? REALLLLLLLLLY DOOD? I'm embarrassed for you. View Quote View All Quotes View All Quotes Quoted:
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So an observer from the ground holding a radar gun would record the projectile having a muzzle velocity of x (2,800 fps, let's say) + y (velocity of the aircraft). So that radar would record a muzzle velocity of 4,800 fps? I don't think so. Your avatar is VERY fitting. It is 4800fps, sherlock. No, it is not 4,800 fps. eta.. how the fuck would ground crews ever be able to regulate the guns if they had to take into account the varying speed of the aircraft? Even at 400 mph that would create problems. JESUS FUCKING CHRIST. REALLY? REALLLLLLLLLY DOOD? I'm embarrassed for you. I AM pretty drunk! But I'm also right. I think. |
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